Re: [Caml-list] zarith: how to pick a random integer?

[basile@starynkevitch.net <basile@starynkevitch.net>]

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On Thursday, November 28, 2019 10:27 CET, basile@starynkevitch.net <basile@starynkevitch.net> wrote:


Sorry for the important typo. Corrected below

On Wednesday, November 27, 2019 22:31 CET, François Pottier <francois.pottier@inria.fr> wrote:
 
Hello,

I am using zarith and would like to pick a random integer
comprised between 0 and some bound. I would like a function
Z.random of type Z.t -> Z.t, but this function seems to be
missing, and I am not sure how to program it in an efficient
and correct way. Any suggestions would be welcome. Thanks!

 
I tend to believe that the following idea might be good, but please check with real probability experts. I definitely am not one (but one of my best colleagues is one).

Let B be the bound.

You take a random number modulus 2*B. Let R be that number

You modelize the [0;B[ interval as a ring of numbers. For example if B is 5 : 0 -> 1 -> 2 -> 3 -> 4 -> 0 -> 1 -> .... ad infinitium


You memoize the previously given random number N

On that ring, you go R steps forward and obtain P. That is your new random number and on the next iteration the N would be that P

But check with an expert, I am not one

--

Basile Starynkevitch http://starynkevitch.net/Basile
 


 

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